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A BLATENT FLAW in Cantor's diag proof

Here is an example of diagonalization

123
456
789

Diag = 159

AntiDiag = 260   <<<<<<<NEW SEQUENCE NOT ON THE LIST!

YOU ALL THINK THIS WORKS ON THE LIST OF COMPUTABLE REALS!

DON’T YOU!!!

Gee it works for 159, must work in the infinite case too, who cares if there’s
no new digit sequence that can be formed.

You’re all DIM!  How can you form a new digit sequence when they’re all
computed up to infinite length?  

Or as George Greene puts it, they’re all computed up to ALL (infinite) FINITE lengths.

And as George Greene puts it there’s a new digit sequence at some FINITE point.

Well I can’t see it.

Herc

the nonexistence of a box that contains the numbers of all the boxes
that don’t contain their own box number implies higher infinities.
– Cantor’s Proof (the holy grail of paradise in mathematics)

Comments (16)




16 Responses to “A BLATENT FLAW in Cantor's diag proof”

  1. admin says:

    On Tue, 8 Jun 2010 12:27:29 +1000, "|-|ercules" <radgray…@yahoo.com>
    wrote:

    >Here is an example of diagonalization

    More meaningless drivel.

  2. admin says:

    On 8/06/2010 12:27 PM, |-|ercules wrote:

    - Hide quoted text — Show quoted text -

    > Here is an example of diagonalization

    > 123
    > 456
    > 789

    > Diag = 159

    > AntiDiag = 260 <<<<<<<NEW SEQUENCE NOT ON THE LIST!

    > YOU ALL THINK THIS WORKS ON THE LIST OF COMPUTABLE REALS!

    > DON’T YOU!!!

    > Gee it works for 159, must work in the infinite case too, who cares if
    > there’s
    > no new digit sequence that can be formed.

    > You’re all DIM! How can you form a new digit sequence when they’re all
    > computed up to infinite length?
    > Or as George Greene puts it, they’re all computed up to ALL (infinite)
    > FINITE lengths.

    > And as George Greene puts it there’s a new digit sequence at some FINITE
    > point.

    > Well I can’t see it.

    > Herc

    As usual, it’s far from clear what you’re on about.

    However, the computable reals are countable, so one could hardly expect
    a diagonalisation argument to show that they’re not, if that’s where
    you’re coming from.

    Sylvia.

  3. admin says:

    "William Hughes" <wpihug…@hotmail.com> wrote

    - Hide quoted text — Show quoted text -

    > On Jun 7, 11:27 pm, "|-|ercules" <radgray…@yahoo.com> wrote:
    >> Here is an example of diagonalization

    >> 123
    >> 456
    >> 789

    >> Diag = 159

    >> AntiDiag = 260   <<<<<<<NEW SEQUENCE NOT ON THE LIST!

    >> YOU ALL THINK THIS WORKS ON THE LIST OF COMPUTABLE REALS!

    >> DON’T YOU!!!

    >> Gee it works for 159, must work in the infinite case too, who cares if there’s
    >> no new digit sequence that can be formed.

    >> You’re all DIM!  How can you form a new digit sequence when they’re all
    >> computed up to infinite length?  

    > You can’t.  So you have a contradiction.  The assumption
    > that there is a list of all real numbers is wrong.

    >                - William Hughes

    You can’t find a new sequence using diagonalization?

    Herc

  4. admin says:

    "Sylvia Else" <syl…@not.here.invalid> wrote …

    - Hide quoted text — Show quoted text -

    > On 8/06/2010 12:27 PM, |-|ercules wrote:
    >> Here is an example of diagonalization

    >> 123
    >> 456
    >> 789

    >> Diag = 159

    >> AntiDiag = 260 <<<<<<<NEW SEQUENCE NOT ON THE LIST!

    >> YOU ALL THINK THIS WORKS ON THE LIST OF COMPUTABLE REALS!

    >> DON’T YOU!!!

    >> Gee it works for 159, must work in the infinite case too, who cares if
    >> there’s
    >> no new digit sequence that can be formed.

    >> You’re all DIM! How can you form a new digit sequence when they’re all
    >> computed up to infinite length?
    >> Or as George Greene puts it, they’re all computed up to ALL (infinite)
    >> FINITE lengths.

    >> And as George Greene puts it there’s a new digit sequence at some FINITE
    >> point.

    >> Well I can’t see it.

    >> Herc

    > As usual, it’s far from clear what you’re on about.

    > However, the computable reals are countable, so one could hardly expect
    > a diagonalisation argument to show that they’re not, if that’s where
    > you’re coming from.

    > Sylvia.

    I think you brainfarted dear.

    Herc

  5. admin says:

    "William Hughes" <wpihug…@hotmail.com> wrote

    - Hide quoted text — Show quoted text -

    > On Jun 7, 11:41 pm, "|-|ercules" <radgray…@yahoo.com> wrote:
    >> "William Hughes" <wpihug…@hotmail.com> wrote

    >> > On Jun 7, 11:27 pm, "|-|ercules" <radgray…@yahoo.com> wrote:
    >> >> Here is an example of diagonalization

    >> >> 123
    >> >> 456
    >> >> 789

    >> >> Diag = 159

    >> >> AntiDiag = 260   <<<<<<<NEW SEQUENCE NOT ON THE LIST!

    >> >> YOU ALL THINK THIS WORKS ON THE LIST OF COMPUTABLE REALS!

    >> >> DON’T YOU!!!

    >> >> Gee it works for 159, must work in the infinite case too, who cares if there’s
    >> >> no new digit sequence that can be formed.

    >> >> You’re all DIM!  How can you form a new digit sequence when they’re all
    >> >> computed up to infinite length?  

    >> > You can’t.  So you have a contradiction.  The assumption
    >> > that there is a list of all real numbers is wrong.

    >> >                - William Hughes

    >> You can’t find a new sequence using diagonalization?

    > Not if you start with a list that does not exist.

    >                      - William Hughes

    I can compute the list of all computable reals.  There’s just some numbers that show
    up blank.

    It’s trivial to compute a list that covers every digit sequence to all (infinite) finite lengths.

    Herc

  6. admin says:

    "the man from havana" <thehouseoftro…@gmail.com> wrote …

    > On Jun 8, 12:27 pm, "|-|ercules" <radgray…@yahoo.com> wrote:
    >> Here is an example of diagonalization

    >> 123
    >> 456

    > give it a rest you junky !

    no prob, last thread

    Herc

  7. admin says:

    On 2010-06-08, |-|ercules <radgray…@yahoo.com> wrote:

    > You’re all DIM!  How can you form a new digit sequence when they’re all
    > computed up to infinite length?  

    You’re begging the question.

    > Well I can’t see it.

    I’m not surprised.

    - Tim

  8. admin says:

    On 2010-06-08, |-|ercules <radgray…@yahoo.com> wrote:

    > I can compute the list of all computable reals.

    No, you can’t.

    > It’s trivial to compute a list that covers every digit sequence to
    > all (infinite) finite lengths.

    Delete "(infinite)", and your statement is correct.  There is no such
    thing as an infinite finite length though, so inserting the word
    "infinite" there makes no sense.

    - Tim

  9. admin says:

    "Tim Little" <t…@little-possums.net> wrote

    > On 2010-06-08, |-|ercules <radgray…@yahoo.com> wrote:
    >> I can compute the list of all computable reals.

    > No, you can’t.

    >> It’s trivial to compute a list that covers every digit sequence to
    >> all (infinite) finite lengths.

    > Delete "(infinite)", and your statement is correct.  There is no such
    > thing as an infinite finite length though, so inserting the word
    > "infinite" there makes no sense.

    How about, all possible digit sequences are computable to all, as in an infinite
    amount of, finite lengths.

    Herc

  10. admin says:

    - Hide quoted text — Show quoted text -

    "Marshall" <marshall.spi…@gmail.com> wrote in message news:753b820e-d8b1-4ecd-b448-283171e2ee02@a39g2000prb.googlegroups.com…
    > On Jun 7, 7:51 pm, "|-|ercules" <radgray…@yahoo.com> wrote:

    >> I can compute the list of all computable reals.  There’s just some numbers that show
    >> up blank.

    >> It’s trivial to compute a list that covers every digit sequence to all (infinite) finite lengths.

    > How are you going to do that?

    > Write a program that first prints out an infinite sequence of zeroes,
    > and then…

    > Oops! Already a problem! There is no "then" that comes after writing
    > the
    > zeroes, because the process of writing the zeroes will never finish.

    > Please show us this trivial program that computes every infinite digit
    > sequence.

    > Marshall

    Here you go:

    1 000000
    2 31415
    3 2818
    4 141
    5 22
    6 7

    It’s not finished yet!  Next digit is the 7th 0 on the first number.

    Herc

  11. admin says:

    "|-|ercules" <radgray…@yahoo.com> wrote in message

    news:875s9fF67sU1@mid.individual.net…

    - Hide quoted text — Show quoted text -

    > "Tim Little" <t…@little-possums.net> wrote
    >> On 2010-06-08, |-|ercules <radgray…@yahoo.com> wrote:
    >>> I can compute the list of all computable reals.

    >> No, you can’t.

    >>> It’s trivial to compute a list that covers every digit sequence to
    >>> all (infinite) finite lengths.

    >> Delete "(infinite)", and your statement is correct.  There is no such
    >> thing as an infinite finite length though, so inserting the word
    >> "infinite" there makes no sense.

    > How about, all possible digit sequences are computable to all, as in an
    > infinite
    > amount of, finite lengths.

    You can’t use delusional paranoia to solve a mathematical problem.

    HR

  12. admin says:

    "HeadRush" <(_!_)@(  .  )(  .  ).com> wrote …

    - Hide quoted text — Show quoted text -

    > "|-|ercules" <radgray…@yahoo.com> wrote in message
    > news:875s9fF67sU1@mid.individual.net…
    >> "Tim Little" <t…@little-possums.net> wrote
    >>> On 2010-06-08, |-|ercules <radgray…@yahoo.com> wrote:
    >>>> I can compute the list of all computable reals.

    >>> No, you can’t.

    >>>> It’s trivial to compute a list that covers every digit sequence to
    >>>> all (infinite) finite lengths.

    >>> Delete "(infinite)", and your statement is correct.  There is no such
    >>> thing as an infinite finite length though, so inserting the word
    >>> "infinite" there makes no sense.

    >> How about, all possible digit sequences are computable to all, as in an
    >> infinite
    >> amount of, finite lengths.

    > You can’t use delusional paranoia to solve a mathematical problem.

    > HR

    What are you saying, The Truman Show is FALSE?

    Herc

  13. admin says:

    On Tue, 8 Jun 2010 14:31:23 +1000, "|-|ercules" <radgray…@yahoo.com>
    wrote:

    >What are you saying, The Truman Show is FALSE?

    Er, yes, it has been all along – only your delusions are "real"…..

  14. admin says:

    "Dingo" <di…@gmail.com> wrote …

    > On Tue, 8 Jun 2010 14:31:23 +1000, "|-|ercules" <radgray…@yahoo.com>
    > wrote:

    >>What are you saying, The Truman Show is FALSE?

    > Er, yes, it has been all along – only your delusions are "real"…..

    Now you get it!

    Herc

  15. admin says:

    "|-|ercules" <radgray…@yahoo.com> wrote in message

    news:875vjnFm6nU1@mid.individual.net…

    > "Dingo" <di…@gmail.com> wrote …
    >> On Tue, 8 Jun 2010 14:31:23 +1000, "|-|ercules" <radgray…@yahoo.com>
    >> wrote:

    >>>What are you saying, The Truman Show is FALSE?

    >> Er, yes, it has been all along – only your delusions are "real"…..

    > Now you get it!

    > Herc

    Now FUCK OFF!!!

  16. admin says:

    On Tue, 8 Jun 2010 14:38:39 +1000, "HeadRush" <(_!_)@(  .  )(  .

    - Hide quoted text — Show quoted text -

    ).com> wrote:

    >"|-|ercules" <radgray…@yahoo.com> wrote in message
    >news:875vjnFm6nU1@mid.individual.net…
    >> "Dingo" <di…@gmail.com> wrote …
    >>> On Tue, 8 Jun 2010 14:31:23 +1000, "|-|ercules" <radgray…@yahoo.com>
    >>> wrote:

    >>>>What are you saying, The Truman Show is FALSE?

    >>> Er, yes, it has been all along – only your delusions are "real"…..

    >> Now you get it!

    >> Herc

    >Now FUCK OFF!!!

    I second that motion…..everyone in favour say "aye"…..motion
    carried unanimously…..

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