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Archive for January, 2010

Re: Number Theory Problem

In article <35516712.127A9…@math.columbia.edu>,
  Richard Carr <c…@math.columbia.edu> wrote:

Before starting, I should point out that I have only a very dim understanding
of the issues involved here, and I don’t know where the references
may be found, but when has that ever stopped anyone on USENET?

- Hide quoted text — Show quoted text -

> I remember reading about this problem on sci.math one time:
> take a natural number n and write it in base 2, with the
> exponents in base 2 etc.
> e.g. 53=2^{2^2+1}+2^{2^2}+2^2+1.
> Then replace the 2′s by 3′s and subtract 1 and write it in base 3.
> 3^{3^3+1}+3^{3^3}+3^3.
> Then replace the 3′s by 4′s and subtract 1 and write it in base 4.
> 4^{4^4+1}+4^{4^4}+4^4-1=4^{4^4+1}+4^{4^4}+3.4^3+3.4^2+3.4+3
> etc.
> The problem is to show that this sequence eventually hits 0,
> independent of which n you start at.

> It is "fairly easy to see" that this is going to happen for any given n,
> although it will generally take a long time to go to 0. For instance, by
> direct computation one finds that if n=4, then one needs to go to the
> (2^{402653211}3-3)rd term (starting at 0)- see below.

> Apparently one cannot prove this for all n in ZFC (although one can for
> individual n) but one can with some large cardinal assumption. I have
> never seen a reference for it though. Does anybody know of such a
> reference? This is to settle an quarrel (not a bet) with a number theory
> colleague that there are number theoretical statements that cannot be
> proven in ZFC but can with additional (large cardinal) assumptions.
> Since my claim was based on this result, which I read about here, I
> assume somebody knows something about it. On the other hand, if I am
> mistaken and you can prove me wrong then that will be equally good.
> Anyway, this guy wants a reference with a proof because he says sci.math
> isn’t a good enough source if without references or proof (which is fair
> enough).

No. This can be settled in ZF. It’s known as Goodstein’s theorem.
What it can’t be proved in is the usual first-order formalization N
of the theory of natural numbers (language including symbols for 0,
successor, + and x, axioms including schema for induction).

The proof of Goodstein is really beautiful. At each stage you have
an expression involving sums and powers of a number k, successively
2, 3, 4 etc. Simply replace this number k by the first infinite ordinal
omega. For instance the first three terms in Richard’s example become

omega^{omega^omega+1}+omega^{omega^omega}+omega^omega+1,

omega^{omega^omega+1}+omega^{omega^omega}+omega^omega, and

omega^{omega^omega+1}+omega^{omega^omega}+omega^3.3+omega^2.3+omega.3+3

etc. Now one sees that these infinite ordinals always form a DECREASING
sequence. By well-ordering the series terminates. This depends on the set of
ordinals below epsilon_0 (the first fixed point of the map a:|–> omega^a)
being well-ordered.

I think the independence proof goes something like this: Gentzen gave
a consistency proof of first order arithmetic N, using the technique
of "cut-elimination". But whay does this not contradict Godel? It’s
because Gentzen’s method used in effect transfinite induction on the
initial segment of ordinals below epsilon_0 (certainly OK in ZF).
This principle can be formalized in N somehow, but the moral of Godel’s
theorem is that this transfinite induction schema contains instances
which are not deducible from the axioms of N. Now I think that from
Goodstein one can deduce this full induction schema and so Goodstein
is not provable in N.

There are other results of this nature: Paris and Harrington proved
a Ramsey-type result which requires transfinite induction up to a much
larger (but still countable) ordinal than epsilon_0. As for large cardinals,
their existence will imply arithmetic results, but as for examples,
my ignorance is total.

Robin Chapman                           + "They did not have proper
Department of Mathematics               –  palms at home in Exeter."
University of Exeter, EX4 4QE, UK       +
r…@maths.exeter.ac.uk                  -    Peter Carey,
http://www.maths.ex.ac.uk/~rjc/rjc.html +      Oscar and Lucinda

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Reminders: FLoC'99 call for workshops and LICS'98 early registration

May 15 is the deadline for both:

    o LICS’98 early registration
      *-*-*-*-*-*-*-*-*-*-*-*-*-*
      (please visit http://www.lics98.cs.indiana.edu to register.
       For additional information about the IEEE Symposium on Logic
       in Computer Science, see
       http://www.bell-labs.com/topic/conferences/lics/), and

    o FLoC’99 workshop proposals
      *-*-*-*-*-*-*-*-*-*-*-*-*-*
      (For the submission procedure, please visit
       http://www.cs.bell-labs.com/cm/cs/what/floc99/cfw.html
       For additional information about the Federated Logic Conference,
       to be held in Trento, Italy, in July 1999, please visit
       http://www.cs.bell-labs.com/cm/cs/what/floc99/index.html)

May 20 is the deadline for making your hotel reservation for LICS’98.
Please check www.lics98.cs.indiana.edu for hotel information.

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UCLA Logic Colloquium, May 15

                         UCLA LOGIC COLLOQUIUM
                         Friday, May 15, 1998
                               4:00 p.m.
                       Mathematical Sciences 6627
                                 UCLA

                             DAVID MARKER
                  (University of Illinois at Chicago)

                    "LOGARITHMIC-EXPONENTIAL SERIES"

The logarithmic-exponential series provide a natural algebraic
nonstandard model of the field of real numbers with exponentiation in
which one can easily analyze asymptotic behavior of definable
functions.  I will show how this model can be used to answer a problem
of Hardy’s.  (This is joint work with Angus Macintyre and Lou van den
Dries.)

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[Q] Large snakes

Hello.

QUESTION:

Given a finite set S of snakes, can one make arbitrarily long snakes by
"chaining" together members of S by their end points?
(Or, equivalently: can one obtain an infinite snake by chaining members
of S; or even: can one obtain an infinite set of distinct snakes by
chaining members of S?)

NB:
– polyminoes are those geomatrical figures obtained by sticking some
  squares together along their sides (so as to come up with a connex
  result);
– a snake is a polyomino p such that the underlying graph (obtained from p
  by placing a vertex at each square of p and joining two vertices iff
  their squares are neighboring) is a path;

examples:

        ###                  ######
        #####                #        #
        ##  #                ##########

        a polyomino          a snake
        (but NOT a snake)

        ####                 ####
           ##                   #o##
                                   ##
        another snake, s        
                             two instances of s chained together
                             by a common endpoint (o)

PROBLEM:

Is that question decidable? Is there any known algorithm to answer it?
More precisely: can it be the case that S yields infinitely many snakes,
but none such that two instances of it could be chained together so as to
form a new snake?
(That is: you never come up with a pattern that could be repeated any
number of times to obtain arbitrarily large snakes; all of the result
snakes cannot be attached to themselves.)

I think I have read somewhere that, given a finite family of polyominoes,
the quetion whether they can pave the plane is undecidable, which makes me
think that this snake problem might be undecidable too. Now I find it hard
to believe that a family of crooked snakes could enable you to build large
snakes while preventing you from making any repeatable pattern…

[BTW: is there any problem that cannot be decided by a TM, but is not
 as hard as the halting problem at the same time? Like if P#NP, then
 there must exist problems in NP that cannot be solved in polynomial
 time, while not being NP-complete.]

Any suggestions, references, etc. are most welcome!

Best regards,

        Yann David
        100552.1…@compuserve.com
        FRANCE

NB: Since I am not a regular reader of this newsgroup,
please e-mail your answers.

"Vous mariez pas, les filles!" – Boris Vian

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integration and differentiation of knowledge

Is there anyone who has rigorous understanding of integration
and differentiation in the continuous case who would be able
to explain the discrete case?
I’ve been looking at Pascals traingle and the most striking
feature of this triangle seems to be the fact that it embodies
(aspects of) integration and differentiation in multiple dimensions in
the discrete case.
For any non-negative number of logical variables, the number of
propositions which have X interpretations can be seen as the surface
area of the propositions which have (X+1) interpretations.
The dimensionality is determined by the number of interpretations, while
the ‘resolution’ is determined by the number of propositional variables.
All propositions for 3 logical variables are partitioned (on the number
of interpretations that satisfy them) as follows:
1 + 8 + 28 + 56 + 70 + 56 + 28 + 8 + 1 = 256

The 8 propositions which have one interpretation are the surface area of
the 28 propositions which have two interpretations. Likewise (except for
the fact that the dimensionality goes from 2 to 3), the 28 propositions
which have three interpretations can be seen as the surface area of
the 56 propositions which have four interpretations.

This link between dimensionality and the triangle of Pascal can be
observed from the following ‘interpretation’:
    1                
   1 1                
  1 2 1              
 1 3 3 1              
1 4 6 4 1            

Every layer indicates how many (spaces), points, lines, faces, volumes,
etc. are involved, given a non-negative number of points.
The first layer, "1", is the case for 0 points.
The second layer, "1 1", is the case for 1 point.
The third layer, "1 2 1", indicates that a line is a
relation between two points.
The fourth layer, "1 3 3 1", indicates that a face is a relation
between three lines which is, in turn, a relation between 3 points.
The fifth layer, "1 4 6 4 1" is simply a tetrahedron.
4 points, 6 lines, 4 faces, 1 volume.

The other (obvious) interpretation is the link between logic and sets
since it demonstrates how propositions can be seen as subsets of
interpretations, while interpretations can be seen as subsets of logical
variables. Every layer in the triangle of Pascal indicates how a powerset
of a given set is partitioned on cardinality. Moreover, since the powerset
is a set itself, certain powersets can be identified with powersets of
powersets. For instance, the 256 propositions in 3 logical variables
can be seen as elements from the powerset of 8 possible interpretations.
Since the powerset of a set of 3 elements has 8 elements, the elements
from the powerset of a set of 8 elements coincide with the elements
from the powerset of (the powerset of a set of 3 elements).
Note that propositions can always be seen as elements from the powerset of
(the powerset of the set of logical variables).
As far as I understand this, I think the powerset operator can be seen as
the way to dualize between propositions and interpretations.
However I don’t understand the exact distinction between interpretations
and propositions although I reckon they can be identified somewhat.

                                                regards, Niek

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ZELENY ARCHIVE NOW ON-LINE

Links to 980 English language posts by Michael Zeleny are
now available at <http://www.samant.com/Z/>.

The page lacks two very necessary features: searching, and
links to the threads in which the posts appeared. I will
need some time to put that in. Please send suggestions for
improvement to scrib…@pobox.com.

Enjoy,

Tushar Samant

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math puzzle contest

New! Solve 10 problems and get a chance to win $25.  Or, solve a logic
problem and get a free registered game.  Please check out our website
www.sheppardsoftware.com  .  Every week you’ll find different problems. New!
Solve 10 problems and get a chance to win $25.  Or, solve a logic problem and
get a free registered game.  Please check out our website
www.sheppardsoftware.com  .  Every week you’ll find different problems.

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http://www.dejanews.com/   Now offering spam-free web-based newsreading

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[Q] BUILDING LARGE SNAKES

Hello.

QUESTION:

Given a finite set S of snakes, can one make arbitrarily long snakes by
"chaining" together members of S by their end points?
(Or, equivalently: can one obtain an infinite set of distinct snakes by
chaining members of S; or even: can one obtain an infinite snake by
chaining members of S?)

NB:
– polyminoes are those geomatrical figures obtained by sticking finitely
  many squares together along their sides (so as to come up with a connex
  result);
– a snake is a polyomino p such that the underlying graph (obtained from p
  by placing a vertex at each square of p and joining two vertices iff
  their squares are neighboring) is a path;

examples:

        ###                  ######
        #####                #        #
        ##  #                ##########

        a polyomino          a snake
        (but NOT a snake)

        ####                 ####
           ##                   #o##
                                   ##
        another snake, s        
                             two instances of s chained together
                             by a common endpoint (o)

PROBLEM:

Is that question decidable? Is there any known algorithm to answer it?
More precisely: can it be the case that S yields infinitely many snakes,
but none such that two instances of it could be chained together so as to
form a new snake?
(That is: you never come up with a pattern that could be repeated any
number of times to obtain arbitrarily large snakes; all of the result
snakes cannot be attached to themselves.)

I think I have read somewhere that the quetion whether a finite family of
polyominoes can pave the plane is undecidable, which makes me think that
this snake problem might be undecidable too. Now I find it hard to believe
that a family of crooked snakes could enable you to build large snakes
while preventing you from making any repeatable pattern…

[BTW: is there any problem that cannot be decided by a TM, but is not
 as hard as (not equivalent to) the halting problem at the same time?
 Like if P#NP, then there must exist problems in NP that cannot be solved
 in polynomial time, while not being NP-complete.]

Any suggestions, references, etc. are most welcome!

Best regards,

        Yann David
        100552.1…@compuserve.com
        FRANCE

NB: Since I am not a regular reader of this newsgroup, please e-mail
your answers.

"Vous mariez pas, les filles!" – Boris Vian

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Re: Great Math Books

Are you crazy? Why do you wanna sell them?

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texts on philosophical topics in modal logic

Does anybody have any advice on introductory texts in modal logic, which
concentrate on the philosophical issues (Quine’s animadversions, Lewis’s
modal realism, etc.) rather than the technical issues?  I am thinking of
philosophical companions to Hughes and Cresswell…

-Phil Kremer

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